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80% => The Nevillew General Discussion Forum => Topic started by: Nijholts Nuts on Sunday, June 6, 2010, 16:20:02



Title: I'll buy a pint for the first TEF'er who can...
Post by: Nijholts Nuts on Sunday, June 6, 2010, 16:20:02
...solve this little conundrum I've just encoutered whilst revising...

A River, 20m wide and 4m deep drains a field that is 3000km square in which the average rain fall is
48cm/Metre Square/Year. One quarter of the rainfall returns to the atmosphere via evaporation but the remainder drains into the river. What is the average speed of the river current?


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Processed Beats on Sunday, June 6, 2010, 16:21:33
Speed = distance/time


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Phil_S on Sunday, June 6, 2010, 16:25:21
You sure the field is 3,000 square Kilometres !
It's a bloody big field !


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: BrightonRed on Sunday, June 6, 2010, 16:43:37
Not sure if this will end anywhere but..

3,000km^2 = 3,000,000,000m^2

48cm = 0.48m

Volume of water that falls annually = 0.48 x 3,000,000,000 = 1,440,000,000m^3

Only 25% exits via the river = 0.25 x 1,440,000,000 = 360,000,000m^3 per year.

So we've got a volume and a period. Just need to think about the rest.


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Nijholts Nuts on Sunday, June 6, 2010, 16:45:27
3/4 exits via the river 1/4 evaporates


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: jonny72 on Sunday, June 6, 2010, 16:48:50
You sure the field is 3,000 square Kilometres !
It's a bloody big field !

Just a little bit smaller than Wiltshire in fact.


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: rich on Sunday, June 6, 2010, 16:53:50
i dont think this can be done from that info. what level is it? ie gcse, A / AS level?


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: BrightonRed on Sunday, June 6, 2010, 16:55:24
ok, 0.75 x 1,440,000,000 = 1,080,000,000m^3 per year

1 year = 31,536,000 seconds

1,080,000,000 / 31,536,000 = 34.25m^3/sec


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: ron dodgers on Sunday, June 6, 2010, 16:56:51
just under 1 mile an hour


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Barry Scott on Sunday, June 6, 2010, 17:01:59
I make it 1.54 mph. The river's current that is. ???


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: BrightonRed on Sunday, June 6, 2010, 17:04:05
Average Velocity = Flow Rate / Cross Sectional Area

= 34.25m^3/sec / 80m^2

0.428m/s

or 0.96 mph


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Nijholts Nuts on Sunday, June 6, 2010, 17:08:53
Its Degree level Engineering, and I believe I owe Brighton Red a pint...well done.


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: leefer on Sunday, June 6, 2010, 17:15:08
Average Velocity = Flow Rate / Cross Sectional Area

= 34.25m^3/sec / 80m^2

0.428m/s

or 0.96 mph

Einstein or what well done BR.....silly question as usual but dosn,t the strength of the wind have any bearing on the flow of a river?


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: ron dodgers on Sunday, June 6, 2010, 17:54:46
Average Velocity = Flow Rate / Cross Sectional Area

= 34.25m^3/sec / 80m^2

0.428m/s

or 0.96 mph
yes - I agree - that's what I said


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Mexicano Rojo on Sunday, June 6, 2010, 18:26:23
bloody hell mr red, you seem like a right thick bumpkin cunt when i have ever been in your company :)


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: The_Plagiarist on Sunday, June 6, 2010, 18:36:48
I'm flying the flag for basic maths on this one: :sherlock:



Field = 3,000,000,000 m2 (3,000 km2)
Rainfall = 0.48m per m2 per year

0.48 x 3,000,000,000 = 1,444,000,000 m3 of rainfall
0.75 of that finds its way into the river = 1,080,000,000 cubic metres of water per year

River crosssection = 80m2 (20 x 4)

so 1,080,000,000 / 80 = 13,500,000 metres of water flows through that river crosssection per year

so the speed = 13,500,000 / 365days / 24hours / 60minutes / 60seconds = 0.428 metres per second


Degree level engineering it aint. :suicide:


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: BANGKOK RED on Sunday, June 6, 2010, 19:21:57
Would it be a constant though.

Surely when the water in the field is deeper, the increased pressure would force it into the river quicker therefore increasing the flow.


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Nijholts Nuts on Sunday, June 6, 2010, 19:33:19
A lot of it is hypothetical, obviously there is no field that is 3000k square and in real life there would be a lot of other contributing factors. I was revising fluid flow so thats all the question encompassed.


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: BANGKOK RED on Sunday, June 6, 2010, 19:36:32
In which case the correct answer would be: "how the fook do you expect me to answer the question without knowing all of the parameters".

It's a bit like asking "How long is a piece of string"


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Nijholts Nuts on Sunday, June 6, 2010, 19:41:46
Degree level engineering it aint. :suicide:

Im a University and it was a tutorial question given to me, you do the maths..


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: Simon Pieman on Sunday, June 6, 2010, 20:26:29
Would it be a constant though.

Surely when the water in the field is deeper, the increased pressure would force it into the river quicker therefore increasing the flow.

That's why it's average flow Einstein ;)


Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: The_Plagiarist on Sunday, June 6, 2010, 20:29:59

you're a university I'm a library, go figure...



Title: Re: I'll buy a pint for the first TEF'er who can...
Post by: BrightonRed on Sunday, June 6, 2010, 22:47:42
Living up to your name then Plagiarist?  ;)

3,000km^2 = 3,000,000,000m^2
48cm = 0.48m
Volume of water that falls annually = 0.48 x 3,000,000,000 = 1,440,000,000m^3
Only 75% exits via the river = 0.75 x 1,440,000,000 = 1,080,000,000m^3 per year
1 year = 31,536,000 seconds
1,080,000,000 / 31,536,000 = 34.25m^3/sec
Average Velocity = Flow Rate / Cross Sectional Area
= 34.25m^3/sec / 80m^2
0.428m/s

I'm flying the flag for basic maths on this one: :sherlock:
Field = 3,000,000,000 m2 (3,000 km2)
Rainfall = 0.48m per m2 per year
0.48 x 3,000,000,000 = 1,444,000,000 m3 of rainfall
0.75 of that finds its way into the river = 1,080,000,000 cubic metres of water per year
River crosssection = 80m2 (20 x 4)
so 1,080,000,000 / 80 = 13,500,000 metres of water flows through that river crosssection per year
so the speed = 13,500,000 / 365days / 24hours / 60minutes / 60seconds = 0.428 metres per second
Degree level engineering it aint. :suicide: