magicroundabout
Fanta Pants
 Offline
Posts: 8746
|
 |
« on: Wednesday, January 9, 2008, 16:09:26 » |
|
|
|
|
|
|
Logged
|
|
|
|
|
land_of_bo
|
|
« Reply #1 on: Wednesday, January 9, 2008, 16:14:43 » |
|
Not really, whatever number you pick the answer is always a multiple of 9 and every ninth image is the same.
|
|
|
|
|
Logged
|
|
|
|
|
red macca
|
|
« Reply #2 on: Wednesday, January 9, 2008, 17:00:21 » |
|
You sure
|
|
|
|
|
Logged
|
|
|
|
herthab
TEF Travel
Offline
Posts: 12020
|
|
« Reply #3 on: Wednesday, January 9, 2008, 17:05:56 » |
|
Not really, whatever number you pick the answer is always a multiple of 9 and every ninth image is the same. I've just done it four times, got four different images and it picked right each time. Explain that, clever bollocks  |
|
|
|
|
Logged
|
It's All Good..............
|
|
|
Ardiles
Offline
Posts: 11528
Stirlingshire Reds
|
|
« Reply #4 on: Wednesday, January 9, 2008, 17:12:26 » |
|
Yes - but look at the images offered for 9, 18, 27, 36 ad infinitum...they will always be the same. Your number will always be a multiple of 9. Can't be bothered with the proof...but it will be. A 14 year old geek could have (and probably did) make that up.
|
|
|
|
|
Logged
|
|
|
|
herthab
TEF Travel
Offline
Posts: 12020
|
|
« Reply #5 on: Wednesday, January 9, 2008, 17:14:04 » |
|
Yes - but look at the images offered for 9, 18, 27, 36 ad infinitum...they will always be the same. Your number will always be a multiple of 9. Can't be bothered with the proof...but it will be. A 14 year old geek could have (and probably did) make that up. But that doesn't explain how it picks the correct symbol from the four possibles, does it? Maybe I'm being a bit thick :? |
|
|
|
|
Logged
|
It's All Good..............
|
|
|
|
land_of_bo
|
|
« Reply #6 on: Wednesday, January 9, 2008, 17:14:12 » |
|
Like ardiles says.
Every time just look at your number and number 9, the image will be the same.
|
|
|
|
|
Logged
|
|
|
|
|
flammableBen
|
|
« Reply #7 on: Wednesday, January 9, 2008, 17:18:35 » |
|
you've got 2 digits right. a and b.
As a number they'll be (10a + b), the sum will be (a + b)
(10a + b) - (a + b) = 10a + b - a - b = 9a.
The number at the end will always be 9 times the first digit. Every 9th picture is the same.
|
|
|
|
|
Logged
|
|
|
|
|
flammableBen
|
|
« Reply #8 on: Wednesday, January 9, 2008, 17:19:55 » |
|
go gcse maths!
|
|
|
|
|
Logged
|
|
|
|
|
BANGKOK RED
|
|
« Reply #9 on: Wednesday, January 9, 2008, 17:19:57 » |
|
Like ardiles says.
Every time just look at your number and number 9, the image will be the same. Righty, the images change for each number every time you start. |
|
|
|
|
Logged
|
|
|
|
herthab
TEF Travel
Offline
Posts: 12020
|
|
« Reply #10 on: Wednesday, January 9, 2008, 17:21:53 » |
|
So I was being thick then Maths was never my strong point! |
|
|
|
|
Logged
|
It's All Good..............
|
|
|
|
BANGKOK RED
|
|
« Reply #11 on: Wednesday, January 9, 2008, 17:25:55 » |
|
So I was being thick then Maths was never my strong point! Not so much the maths side of it. I missed the fact the number 9 symbol changed each time myself. Similar to many card tricks, that's all. |
|
|
|
|
Logged
|
|
|
|
herthab
TEF Travel
Offline
Posts: 12020
|
|
« Reply #12 on: Wednesday, January 9, 2008, 17:27:59 » |
|
You've all spoilt it for me.
Next you'll be telling me that Paul Daniels can't really saw a woman in half!
|
|
|
|
|
Logged
|
It's All Good..............
|
|
|
|
land_of_bo
|
|
« Reply #13 on: Wednesday, January 9, 2008, 17:29:54 » |
|
I wish he'd saw "the lovely debbie mcgeeeeeeeeeeeee" in half!
|
|
|
|
|
Logged
|
|
|
|
Samdy Gray
Dirty sneaky traitor weasel
Offline
Posts: 27137
|
|
« Reply #14 on: Wednesday, January 9, 2008, 18:04:55 » |
|
you've got 2 digits right. a and b.
As a number they'll be (10a + b), the sum will be (a + b)
(10a + b) - (a + b) = 10a + b - a - b = 9a.
The number at the end will always be 9 times the first digit. Every 9th picture is the same. Simple, innit. |
|
|
|
|
Logged
|
|
|
|
|
